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Post by Scott on Jul 19, 2010 6:55:49 GMT -5
A fireball has a 40' diameter as a sphere. What would the diameter be for a hemisphere blast, i.e. you're attacking gound level targets and not shooting it into the sky?
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Post by Scott on Jul 19, 2010 7:16:06 GMT -5
I come up with just over 50' diameter using a formula I found online. Anybody come up with anything different?
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Falconer
Enchanter
Knight Bachelor
AD&D, Middle-earth, Star Trek TOS
Posts: 330
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Post by Falconer on Jul 21, 2010 2:54:45 GMT -5
It’s an interesting question. Would the spell be cast at the floor or 4' above? I wouldn’t know how to calculate that. And, to be honest, in actual gameplay I probably wouldn’t bother to even fake it. I’d just (in most cases) figure it out 2-dimensionally, under the assumption that the intent of the spell already takes the ground into consideration. Something like this (breaking it down into 2.5' squares within the usual 10' squares): That’s an open space. If you’ve got walls converging in the space you just take the squares it would displace and add them on the end in the direction they would go:
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Post by Scott on Jul 21, 2010 6:27:48 GMT -5
I found a calculator online that figures out various properties of different shapes based on other known properties, and a hemisphere blast with 33,000 cubic feet volume would have a 50' diameter. The same formula comes up with a 40' diameter sphere sphere, which matches the figures in the PH. Confined areas are easier to calculate, since you can usually just count 33 10' cubes.
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Post by Scott on Jul 21, 2010 12:35:06 GMT -5
It’s an interesting question. Would the spell be cast at the floor or 4' above? Aiming at the floor would give you the widest diameter; 4' above would be a small difference, around 3 feet, which would be about 1 1/2 feet difference on each side of the blast. I'd just keep the diameter at 50'.
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